In binary notation, what is the decimal equivalent of 41?

In binary notation, what is the decimal equivalent of 41?

• A. 00010101
• B. 00101001
• C. 01000001
• D. 00110001

Answer: (B)

To determine the decimal equivalent of the binary number that corresponds to 41, we need to consider how binary numbers are constructed. Each digit in a binary number represents a power of 2, starting from the rightmost digit which represents \(2^0\), then moving leftwards to \(2^1\), \(2^2\), and so forth. The binary number for 41 is 101001, which can be understood as follows: - The rightmost bit is \(1\), which is \(2^0 = 1\). - The second bit from the right is \(0\), which is \(0 \times 2^1 = 0\). - The third bit is \(0\), which is \(0 \times 2^2 = 0\). - The fourth bit is \(1\), which is \(1 \times 2^3 = 8\). - The fifth bit is \(0\), which is \(0 \times 2^4 = 0\). - The leftmost bit is \(1\), which is \(1 \times 2^5 = 32\). Now, when we add these values together, we get: \(32

To determine the decimal equivalent of the binary number that corresponds to 41, we need to consider how binary numbers are constructed. Each digit in a binary number represents a power of 2, starting from the rightmost digit which represents (2^0), then moving leftwards to (2^1), (2^2), and so forth.

The binary number for 41 is 101001, which can be understood as follows:

• The rightmost bit is (1), which is (2^0 = 1).

• The second bit from the right is (0), which is (0 \times 2^1 = 0).

• The third bit is (0), which is (0 \times 2^2 = 0).

• The fourth bit is (1), which is (1 \times 2^3 = 8).

• The fifth bit is (0), which is (0 \times 2^4 = 0).

• The leftmost bit is (1), which is (1 \times 2^5 = 32).

Now, when we add these values together, we get:

(32